(w+4)^2=2w^2+4w+19

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Solution for (w+4)^2=2w^2+4w+19 equation: 



(w+4)^2=2w^2+4w+19

We move all terms to the left:

(w+4)^2-(2w^2+4w+19)=0

We get rid of parentheses

-2w^2+(w+4)^2-4w-19=0

We add all the numbers together, and all the variables

-2w^2-4w+(w+4)^2-19=0

We move all terms containing w to the left, all other terms to the right

-2w^2-4w+(w+4)^2=19

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